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  4. The energy of a photon of light of wavelength 450 nm is:

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Q. The energy of a photon of light of wavelength 450 nm is:

JIPMERJIPMER 2000

Solution:

From the relation $ E=hv=\frac{hc}{\lambda }=\frac{6.62\times {{10}^{-34}}\times 3\times {{10}^{8}}}{450\times {{10}^{-19}}} $ $ =4.4\times {{10}^{-19}}J $