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Q.
The energy of a photon corresponding to the visible light of maximum wavelength is approximately
Dual Nature of Radiation and Matter
Solution:
Energy of photon, E = $ \frac{ 12375 }{ \lambda \, ( in \, \mathring{A} ) } e V $
For red light the wavelength is maximum.
$ \because \lambda_R = 7900 \mathring{A} $
$ \therefore E = \frac{ 12375 }{ 7900 } e V $
= 1.5 e V $ \simeq $ 1.6 e V