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Q. The energy needed to remove the one electron from neutral helium atom is $24.6\, eV$. Then the energy needed to remove both the electrons from neutral helium atom is

Rajasthan PETRajasthan PET 2003

Solution:

$ E=13.6\times \frac{{{(Z)}^{2}}}{1}=54.4eV $ Total energy $ =24.6+54.4=79\text{ }eV $