Question

The energy in $ MeV $ is released due to transformation of $ 1\,\,kg $ mass completely into energy $ (c=3\times {{10}^{8}}m/s) $ :

• A. $ 7.625\times 10\,\,MeV $
• B. $ 10.5\times {{10}^{29}}\,\,MeV $
• C. $ 2.8\times {{10}^{-28}}\,\,MeV $
• D. $ 5.625\times {{10}^{29}}\,\,MeV $

Answer 1

Answer: (D)

According to Einstein's mass energy equivalence
$E =m c^{2}=1 \times\left(3 \times 10^{8}\right)^{2} $
$=9 \times 10^{16} J $
$=\frac{9 \times 10^{16}}{1.6 \times 10^{-13}} MeV$
(since $ 1 \, MeV =1.6 \times 10^{-13} J ) $
$=5.625 \times 10^{29} MeV$