1. Tardigrade
  2. Question
  3. Chemistry
  4. The end product (Z) in the given sequence of reaction is CH3CH = CHCHO xrightarrowNaBH4 X xrightarrow[ZnCl2]HClY xrightarrow[(ii)H+](i) KCN Z

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Q. The end product $(Z)$ in the given sequence of reaction is
$CH_{3}CH = CHCHO \xrightarrow{NaBH_{4}} X \xrightarrow[ZnCl_{2}]{HCl}Y \xrightarrow[(ii)H^{+}]{(i) KCN} Z$

Aldehydes Ketones and Carboxylic Acids

Solution:

Correct answer is (a) $CH_{3}CH = CHCH_{2}COOH$

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