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Q. The empirical formula of a compound is $CH_2O$ and its molecular mass is 120. The molecular formula of the compound is

Some Basic Concepts of Chemistry

Solution:

E.F. mass $=12+2\times1+16=30$
Mol. mass $= 120$
$n=\frac{\text{Mol.mass}}{\text{E.F. mass}}$
$=\frac{120}{30}=4$
$\therefore $ Mol. formula $=(CH_{2}O)_{4}$
$=C_{4}H_{8}O_{4}$