1. Tardigrade
  2. Question
  3. Chemistry
  4. The emf of a Daniell cell at 298 K is E1 Zn/ZnSO4(0.01 text M)||CuSO4 text(1 text.0 textM) ! !| ! ! text Cu When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M. The emf changed to E2 . What is the relation between E1 and E2 ?

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Q. The emf of a Daniell cell at 298 K is $ {{E}_{1}} $ $ Zn/ZnS{{O}_{4}}(0.01\text{ }M)||CuS{{O}_{4}}\text{(1}\text{.0}\,\text{M) }\!\!|\!\!\text{ }Cu $ When the concentration of $ ZnS{{O}_{4}} $ is 1.0 M and that of $ CuS{{O}_{4}} $ is 0.01 M. The emf changed to $ {{E}_{2}} $ . What is the relation between $ {{E}_{1}} $ and $ {{E}_{2}} $ ?

KEAMKEAM 2000

Solution:

$ {{E}_{2}}={{E}_{1}}-\frac{0.0591}{n}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]} $ $ {{E}_{2}}={{E}_{1}}-\frac{0.0591}{2}\log \frac{1}{0.01} $ $ {{E}_{2}}={{E}_{1}}-0.0591 $ Hence, $ {{E}_{1}}>{{E}_{2}} $