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Q. The elevator shown in figure is descending with an acceleration of $2 \,ms^{-2}$ The mass of the block $A = 0.5\, kg$. The force exerted by the block A on the block B is: Take $g = 10 \,m/s^{2}$
image

Laws of Motion

Solution:

Let $A$ applies a force $R$ on $B$,
Then B also applies an opposite force R on A as shown
image
For $A : mg -R =ma$
$\Rightarrow R=m(g-a)$
$=0.5[10-2] =4\,N$