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  4. The electrostatic force on a small sphere of charge 0.4 μ C due to another small sphere of charge -0.8 μ C in air is 0.2 N. The distance between the two spheres is

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Q. The electrostatic force on a small sphere of charge $0.4\, \mu C$ due to another small sphere of charge $-0.8 \, \mu C$ in air is $0.2\, N$. The distance between the two spheres is

Electric Charges and Fields

Solution:

$ F=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0} r^{2}}$
$\Rightarrow r^{2}=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0} \cdot F}=\frac{\left(9 \times 10^{9}\right)\left(0.4 \times 10^{-6}\right)\left(0.8 \times 10^{-6}\right)}{0.2}$
$\therefore r^{2}=144 \times 10^{-4} \Rightarrow r=12 \times 10^{-2} m =12\, cm$