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Chemistry
The electronic configuration of silver atom in ground state is
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Q. The electronic configuration of silver atom in ground state is
Structure of Atom
A
$[Kr] 3d^{10} 4s^{1}$
17%
B
$[Xe] 4f^{14} 5d^{10} 6s^{1}$
30%
C
$[Kr] 4d^{10} 5s^{1}$
37%
D
$[Kr] 4d^{9} 5s^{2}$
16%
Solution:
The electronic configuration of $Ag$ in ground state is $[Kr]4d^{10} 5s^{1}$