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Q. The electronic configuration of an element is $1s^2,2s^2 2p^6,3s^2 3p^3$. What is the atomic number of the element, which is present just below the above element in the periodic table?

AIPMTAIPMT 1995Classification of Elements and Periodicity in Properties

Solution:

The element which present just below this element will have outermost electronic configuration as $4s^2 4p^3$, so its full electronic configuration is $1s^2, 2s^2 2p^6, 3s^2 3p^6, 4s^2,$ $3d^{10}, 4p^3$ and hence, its atomic number is 33.