Question

The electronic configuradon of nitrogen can be expressed as

• A. $1 s^{2}, 2 s^{2}, 2 p_{x}^{2}\, p_{y}^{1} \,p_{z}^{0}$
• B. $1 s^{2}, 2 s^{2}, 2 p_{x}^{1}, p_{y}^{1}, p_{z}$
• C. $1 s^{2}, 2 s^{2}, 2 p_{x}^{3}, p_{y}^{0}, p_{z}^{0}$
• D. $1 s^{2}, 2 s^{2}, 2 p_{x}^{1}, p_{y}^{2}, p_{z}^{0}$

Answer 1

Answer: (B)

Nitrogen $(7)$, electronic configuration $=1 s^{2}, 2 s^{2}, 2 p_{x}, 2 p_{y}, 2 p_{z}^{1}$
Note : According Hund's rule, “Pairing of electrons in various orbitals (like $p_{x}, p_{y ;}, p_{z}$ ) of a suborbit like $(np)$ take place only after each orbital is half filled/singly occupied".