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Chemistry
The electronegativities of N, C, Si and P are in the order
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Q. The electronegativities of $N, C, Si$ and P are in the order
KEAM
KEAM 2018
Some Basic Concepts of Chemistry
A
P < Si < C < N
7%
B
Si < P < N < C
22%
C
Si < P < C < N
70%
D
P < Si < N < C
0%
E
Difficult to predict
0%
Solution:
Electronegativity increases on moving left to right in a period and decreases for the period below it $(\because n=$ increases $)$
$\because( N$ and $C )$ and $( Si$ and $P )$ respectively belongs to $(n=2)$ and $(n=3)$
$\therefore $ Electronegativity of $N >$ electronegativity of $C$ and electronegativity of $P >$ electronegativity of $Si$ Hence, correct order is:
$Si < P < C < N$