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Q. The electron configuration of the oxide ion is much most similar to the electron configuration of the

UPSEEUPSEE 2009

Solution:

Species having the same number of electrons as in oxide ion, has the same electronic configuration as oxide ion.

In oxide ion $\left( O ^{2-}\right)$, number of electrons $=8+2=10$

In sulphide ion $\left( S ^{2-}\right)$, number of electrons $=16+2=18$

In nitride ion $\left( N ^{3-}\right)$, number of electrons $=7+3=10$

In oxygen atom and nitrogen atom, number of electrons $=8,7$ respectively.

Hence, electronic configuration of

$O ^{2-}$ or $N ^{3-}(10)=\sigma 1 s^{2}, \overset{*}{\sigma} 1 s^{2}, \sigma 2 s^{2}, \overset{*}{\sigma} 2 s^{2}, \pi 2 p_{x}^{1} \approx \pi 2 p_{y}^{1}$