Question

The electron affinity values (in kJ $ mo{{l}^{-1}} $ ) of three halogens X, Y, Z are respectively -349, -333 and -325. Then X, Y and Z respectively are

• A. $ {{F}_{2}},\,C{{l}_{2}} $ and $ B{{r}_{2}} $
• B. $ C{{l}_{2}},\,{{F}_{2}} $ and $ B{{r}_{2}} $
• C. $ C{{l}_{2}},\,B{{r}_{2}} $ and $ {{F}_{2}} $
• D. $ B{{r}_{2}},\,C{{l}_{2}} $ and $ {{F}_{2}} $

Answer 1

Answer: (B)

Electron affinity (in kJ $ \text{mo}{{\text{l}}^{\text{-1}}} $ ) of F = 332.6, Cl = 348.5, Br = 324.7 and I = 295.5. Chlorine has highest electron affinity value, So, according to question the correct order will be $ C{{l}_{2}}>{{F}_{2}}>B{{r}_{2}} $ .