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Q. The electron affinity of iodine is $4.9 \times 10^{-19} \,J /$ atom. The electron gain enthalpy of iodine in $eV$ per atom is___.

Classification of Elements and Periodicity in Properties

Solution:

Electron affinity $=4.9 \times 10^{-19} J / atom$
$\therefore $ Electron gain enthalpy $=-4.9 \times 10^{-19} J /\,atom$
Now, $1 eV =1.6 \times 10^{-19} J$
$\therefore $ Electron gain enthalpy
$=-4.9 \times 10^{-19} J / atom \times \frac{1 \,eV }{1.6 \times 10^{-19} J }$
$=-3.06\, eV / atom $