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Q. The electrolysis of acetate solution produces ethane according to reaction -
$2 CH _{3} COO ^{-} \longrightarrow C _{2} H _{6}( g )+2 CO _{2}( g )+2 e ^{-}$
The current efficiency of the process is $80 \%$. What volume of gases would be produced at $27^{\circ} C$ and $740$ torr, if the current of $0.5$ amp is passed through the solution for $96.45\, \min$ ?

Electrochemistry

Solution:

Equivalents of $CO _{2}$ produced $=\frac{( I \times \eta ) \times t }{96500}$
$\frac{0.5 \times 0.8 \times 96.5 \times 60}{96500}=0.024$
moles of $CO _{2}( n =1)$ produced $=0.024$
moles of $C_{2} H_{6}(n=2)$ produced
$=\frac{0.024}{2}=0.012$
Total moles of gases produced $\Rightarrow 0 . 036$
$V_{\text {gases }}=\frac{n R T}{P}=\frac{0.036 \times 0.0821 \times 300}{\left(\frac{740}{760}\right)}$
$=0.91$ litre