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Q. The electric potential in volts due to an electric dipole of dipole moment $2 \times 10^{-8}$ coulomb-metre at a distance of $3 \,m$ on a line making an angle of $60^{\circ}$ with the axis of the dipole is

Electrostatic Potential and Capacitance

Solution:

$V=\frac{9 \times 10^{9} \times 2 \times 10^{-8} \times \frac{1}{2}}{9}=10 \,V$