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Physics
The electric potential energy of the system of three charges given in figure is
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Q. The electric potential energy of the system of three charges given in figure is
A
$-7.47\, J$
15%
B
$7.47 \,J$
15%
C
$-7.45 \times 10^{-5} \,J$
38%
D
$7.47 \times 10^{-5} \,J$
31%
Solution:
$U=\frac{9 \times 10^{9} \times 10^{-12}}{10^{-1}} $
$\left[-\frac{8 \times 15}{3}-\frac{15 \times 20}{4}+\frac{20 \times 8}{5}\right]$
$U =-7.47\, J$