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  4. The electric potential at the centre of a hemisphere of radius R and having surface charge density σ is

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Q. The electric potential at the centre of a hemisphere of radius R and having surface charge density $\sigma$ is

Electrostatic Potential and Capacitance

Solution:

$V = \frac{1}{4 \, \pi \, \varepsilon_0} \frac{Q}{R} = \frac{1}{4 \, \pi \, \varepsilon_0} \frac{( 4 \, \pi \, R^2 \, \sigma/ 2 )}{R} = \frac{R \, \sigma}{2 \, \varepsilon_0}$