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Physics
The electric field required to keep a water drop of mass in just to remain suspended, when charged with one electron:
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Q. The electric field required to keep a water drop of mass in just to remain suspended, when charged with one electron:
JIPMER
JIPMER 1998
A
$ \text{em/g} $
B
$ \text{mg/e} $
C
$ \text{emg} $
D
$ \text{mg} $
Solution:
Here: mass of water drop $ =m, $ so, weight of water drop $ =mg $ so, $ mg= $ electrostatic force applied by the field $ mg=qE=eE\,\,\,\Rightarrow \,\,\,E=\frac{mg}{e} $