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Q. The electric field required to keep a water drop of mass in just to remain suspended, when charged with one electron:

JIPMERJIPMER 1998

Solution:

Here: mass of water drop $ =m, $ so, weight of water drop $ =mg $ so, $ mg= $ electrostatic force applied by the field $ mg=qE=eE\,\,\,\Rightarrow \,\,\,E=\frac{mg}{e} $