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  4. The electric field intensity at P and Q, in the shown arrangement, are in the ratio

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Q. The electric field intensity at $P$ and $Q$, in the shown arrangement, are in the ratioPhysics Question Image

Electric Charges and Fields

Solution:

$E_{p}=\frac{k q}{r^{2}}\,\,\,...(i)$
$E_{Q}=\frac{k q}{(2 r)^{2}}+\frac{k \cdot 3 q}{(2 r)^{2}}$
$=\frac{k q}{4 r^{2}}+\frac{k \cdot 3 q}{4 r^{2}}$
$=\frac{k q}{r^{2}}\,\,\,...(ii)$
$E_{P}: E_{Q}=1: 1$