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Q. The electric field intensity at all points in space is given by $\vec{E}=(\sqrt{3} \hat{i}-\hat{j}) \quad Vm ^{-1}$. The nature of equipotential lines in $x-y$ plane, is shown by

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Solution:

The direction of uniform electric field in $x-y$ plane is as shown
Solution
Solution
The equipotential lines will be perpendicular to electric field. Also electric field points from high potential region towards low potential region. Therefore nature of equipotential lines in $x-y$ plane is as shown in option $3$