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Q. The electric field in a region is given by $\vec{E} = \left(Ax + B\right)\hat{i}$ where $E$ is in $NC^{-1}$and $x$ is in metres. The values of constants are $A \,= \,20 SI$ unit and $B \,= \,10 SI$ unit. If the potential at $x = 1$ is $V_{1}$ and that at $x = -5$ is $V_{2}$, then $V_{1} - V_{2}$ (in volt) is:

Electrostatic Potential and Capacitance

Solution:

Given, $\vec{E}=(A x+B) \hat{i}$
or $E=20 x+10$
Using $V=\int E d x$, we have
$ V_{2}-V_{1}=\int_{-5}^{1}(20 x+10) d x=-180 V $
or $V_{1}-V_{2}=180 V$