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Physics
The electric field E, current density J and conductivity σ of a conductor are related as
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Q. The electric field $E$, current density $J$ and conductivity $\sigma$ of a conductor are related as
Current Electricity
A
$\sigma=E / J$
13%
B
$\sigma=J / E$
77%
C
$\sigma=J^{2} E$
6%
D
$\sigma=\frac{1}{J E}$
4%
Solution:
$J=\sigma E$ or $\sigma=J / E$