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  4. The electric field components in the given figure are Ex = α x1/2, Ey = Ez = 0 in which α = 800 N C-1 m-1/2. The charge within the cube if net flux through the cube is 1.05 N m2 C-1 (assume a = 0.1 m)

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Q. The electric field components in the given figure are $E_x = \alpha x^{1/2}$, $E_y = E_z = 0$ in which $\alpha = 800\, N\, C^{-1}\, m^{-1/2}$. The charge within the cube if net flux through the cube is $1.05\, N\, m^2\,C^{-1}$ (assume $a = 0.1\, m$)Physics Question Image

Electric Charges and Fields

Solution:

By Gauss’s law, $\phi=\frac{q}{\varepsilon_{0}}$
or $q=\phi\varepsilon_{0}$
$=1.05\times8.854\times10^{-12}\,C$
$=9.27\times10^{12}\,C$