Q. The electric field at the point associated with a light wave is given by $E=200\left[\sin \left(6 \times 10^{15}\right) t +\sin \left(9 \times 10^{15}\right) t \right] Vm ^{-1}$ Given : $h =4.14 \times 10^{-15} eVs$ If this light falls on a metal surface having a work function of $2.50\, eV$, the maximum kinetic energy of the photoelectrons will be :
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