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Q. The efficiency of a Carnot engine working between $\text{800 K}$ and $\text{500 K}$ is -

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

Efficiency, $\eta=1-\frac{T_{2}}{T_{1}}=1-\frac{500}{800}$
$ \, \, \, =\frac{3}{8}=0.375$