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Q.
The efficiency of a Carnot engine operating between reservoirs maintained at temperatures $27^{\circ}C $ and $=123^{\circ}C$ is:
Delhi UMET/DPMTDelhi UMET/DPMT 2002
Solution:
The efficiency $(\eta)$ of Carnot engine is defined as the amount of work divided by the heat transferred between the system and the hot reservoir. i.e., $\eta =\frac{\Delta \,W}{\Delta \,Q_{H}}=1-\frac{T_{C}}{T_{H}}$
Given, $T_{H}=27^{\circ}C=273+27=300\,K$,
$T_{C}=-123^{\circ}C=273-123=150\,K $
$\therefore \eta =1-\frac{150}{300}=0.5$