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Q.
The edge lengths of the unit cells in terms of the radius of spheres constituting $fcc$, $bcc$ and simple cubic unit cell are respectively
The Solid State
Solution:
In FCC: The atoms at the face diagonals touch each. If a is the edge length of cube and $r$ is the radius of the atom.
So, $\sqrt{2} a =4 r$
$
\Rightarrow a =2 \sqrt{2} r
$
In bcc: The atoms at the body diagonal touch each other.
So, $\sqrt{3} a=4 r$
$
\Rightarrow a =\frac{4}{\sqrt{3}} r
$
In simple cubic: The atoms at the corners touch each other. So, $a=2 r$