1. Tardigrade
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  3. Chemistry
  4. The edge length of the unit cell of NaCl crystal lattice is 5.623 mathringA, density is 2.16 g cm-3 and the molar mass of NaCl is 58.5 g mol-1. The number of moles per unit cell is

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Q. The edge length of the unit cell of $NaCl$ crystal lattice is $5.623\mathring{A}$, density is 2.16 $g cm^{-3}$ and the molar mass of $NaCl$ is $58.5\, g$ $mol^{-1}$. The number of moles per unit cell is

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Solution:

$Z = \frac{\rho a^{3}N_{A}}{M}$
$= \frac{2.16\times \left(5.623\times 10^{-8}\right)^{3}\times 6.02 \times 10^{23}}{58.5} $
$= 3.95\approx4$