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  4. The edge length of a fcc ionic crystal is 508 pm. If the radius of cation is 110 pm, the radius of anion will be

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Q. The edge length of a $fcc$ ionic crystal is 508 pm. If the radius of cation is 110 pm, the radius of anion will be

JIPMERJIPMER 2016The Solid State

Solution:

For ionic compounds,
Edge length $(a)=2\left(r_{+}+r_{-}\right)$
$508=2\left(110+r_{-}\right) $
$508=220+2 r_{-} $
$2 r-=508-220=288 \,pm$
$r_{-}=144 \,pm$