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Q. The eccentricity of the conic $ 9{{x}^{2}}+25{{y}^{2}}=225 $ is:

KEAMKEAM 2002

Solution:

The given equation is $ \frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{9}=1 $ The eccentricity, $ e=\sqrt{1-\frac{9}{25}} $ $ =\sqrt{\frac{16}{25}} $ $ =\frac{4}{5} $