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  4. The eccentricity of the conic 3 x2+4 y2-6 x-8 y+4=0

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Q. The eccentricity of the conic $3 x^{2}+4 y^{2}-6 x-8 y+4=0$

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Solution:

by short cut $e =\sqrt{\frac{B-A}{B}}=\sqrt{\frac{4-3}{4}}=\frac{1}{2}$