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Q. The eccentricity of an ellipse, with its centre as origin, is $\frac{1}{2}$ . If one of the directrices is $x=4$. then the equation of the ellipse is given by_______

AP EAMCETAP EAMCET 2020

Solution:

Centre $=(0,0)$
Eccentricity $(e)=\frac{1}{2}$
Equation of directrix is $x=4$
$\Rightarrow \frac{a}{e}=4$
$\Rightarrow a=4 e$
$\Rightarrow a=2$
$b^{2}=a^{2}\left(1-e^{2}\right)$
$=4\left(1-\frac{1}{4}\right)$
$b^{2}=3$
$\therefore $ Required Equation of Ellipse is
$\frac{x^{2}}{4}+\frac{y^{2}}{3}=1$
$3 x^{2}+4 y^{2}=12$