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Q. The driver of a car moving towards a rocket launching pad with a speed of $6\, m / s$ observes that the rocket is moving with speed of $10\, m / s$. The upward speed of the rocket as seen by the stationary observer is

ManipalManipal 2019

Solution:

Observed speed, $v=\sqrt{(10)^{2}+(6)^{2}}$
$=\sqrt{100+36}=\sqrt{136} \approx 11\, m / s$