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Q. The drift velocity of the electrons in a copper wire of length $2\,m$ under the application of a potential difference of $220\,V$ is $0.5$ $m s^{- 1}$ . Their mobility (in $m^{2}V^{- 1}s^{- 1}$ )

NTA AbhyasNTA Abhyas 2022

Solution:

Drift velocity = mobility× intensity of the electric field
or $v_{d}=\mu E \, or \, \mu =\frac{v_{d}}{E}$
$or \, \mu =\frac{v_{d}}{V / l} \, \left(\because E = \frac{V}{l}\right)$
$\therefore \mu =\frac{0.5 \times 2}{220}=4.5\times 10^{- 3}m^{2}V^{- 1}s^{- 1}$