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Q. The drain cleaner, Drainex contains small bits of aluminium which react with caustic soda to produce dihydrogen. What volume of dihydrogen at 20 °C and one bar will be released when 0.15 g of aluminium reacts?

States of Matter

Solution:

The reaction between aluminium and caustic soda is
$2Al + 2NaOH + 2H_2O → 2NaAlO_2 + 3H_2$
$2 × 27 = 54 \,g \quad 3 × 22.4\, L$ at $STP$
$\therefore 54 \,g$ of $Al$ produces $H_2$ at $STP = 3 × 22.4 L$
$0.15\, g$ of Al will produce $H_2$ at $STP$
$=\frac{3\times22.4}{54}\times0.15=0.186\,L$
At $STP$ Given conditions
$P_{1}=1\,atm\,P_{2}=1\,bar=0.987\,atm$
$V_{1}=0.186\,L\,V_{2}=?$
$T_{1}=273\,K\,T_{2}=273+20=293\,K$
Applying ideal gas equation, $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$
$\frac{1\times0.1867}{273}=\frac{0.987\times V_{2}}{293}$
$V_{2}=\frac{293}{0.987}\times\frac{1\times0.1867}{273}=0.2030\,L=203\,mL$