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Q.
The domain of the real function $f(x)=\frac{1}{\sqrt{4-x^2}}$ is
Relations and Functions
Solution:
$f(x)$ assumes real values, if
$4-x^2 >0$
$\Rightarrow x^2-4< 0$
$\Rightarrow (x+2)(x-2)<0$
$\Rightarrow x \in(-2,2)$
$\therefore $ Domain of $f=(-2,2)$