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Q.
The distance travelled by a particle starting from rest and moving with an acceleration $\frac{4}{3}ms^{-2},$ in the third second is
AIPMTAIPMT 2008Motion in a Straight Line
Solution:
Distance travelled in the $3^{\text{rd}}$ second
= Distance travelled in $3\,s - $ distance travelled in $2 \,s$.
As, $u=0$,
$S_{\left(3^{\text{rd }} s \right)}=\frac{1}{2} a \cdot 3^{2}-\frac{1}{2} a \cdot 2^{2}=\frac{1}{2} \cdot a \cdot 5$
Given $a=\frac{4}{3} ms ^{-2} ; $
$\therefore S_{\left(3^{\text {rd }} s \right)}=\frac{1}{2} \times \frac{4}{3} \times 5=\frac{10}{3} m$