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Q. The distance travelled by a particle is proportional to the squares of time, then the particle travels with :- $\left(S \alpha t^{2}\right)$

NTA AbhyasNTA Abhyas 2020

Solution:

$s \propto t^{2}$
$s=kt^{2}$ ( $c=$ constant)
$v=\frac{d s}{d t}=2kt$ (Increasing velocity)
$acca=\frac{d v}{d t}=2k$
Uniform acceleration