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Q. The distance of the Sun from earth is $1.5 \times 10^{11}\, m$ and its angular diameter is $(2000) \,s$ when observed from the earth. The diameter of the Sun will be :

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Solution:

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$\frac{2000}{60 \times 60} \times \frac{\pi}{180}=\frac{ d }{1.5 \times 10^{\prime \prime}}$
$\Rightarrow d =\frac{2000}{60 \times 60} \times \frac{\pi}{180} \times 1.5 \times 10^{\prime \prime}$
$=\frac{\pi \times 1.5}{3 \times 6 \times 18} \times 10^{\prime \prime}=1.45 \times 10^{9}$