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Q.
The distance of point $P(3,4, 5)$ from the $yz$-plane is
Introduction to Three Dimensional Geometry
Solution:
When we draw a perpendicular line from $P(3, 4, 5)$ on the $yz$-plane, the $x$-coordinate will be zero, and they and $z$-coordinates be $4$ and $5$ respectively.
$\therefore $ Coordinate of a point on $yz$-plane be $Q\left(0,4,5\right)$
$\therefore PQ = \sqrt{\left(3-0\right)^{2}+\left(4-4\right)^{2}+\left(5-5\right)^{2}}= 3$ units