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  4. The distance between two magnetic pole is doubled and the pole strength of each is halved, the force between them will be

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Q. The distance between two magnetic pole is doubled and the pole strength of each is halved, the force between them will be

Solution:

Here $F = \frac{\mu_0}{4 \, \pi} \frac{q_m \, q_m}{r^2}$
when pole strength is halved and distance is doubled, the force becomes
$F' = \frac{\mu_0}{4 \,\pi} \frac{q_m \, q_m/4}{(2r)^2} = \frac{F}{16}$