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Q. The distance between two consecutive crests in a wave train produced in string is $5\, cm$. If two complete waves pass through any point per second, the velocity of wave is:

Haryana PMTHaryana PMT 2002

Solution:

Distance between two consecutive crests $=5\, cm$
$\therefore $ wavelength $\lambda=5\, cm$
frequency $n=2$
$\therefore $ velocity $v=n \lambda$
$=2 \times 5=10\, cm / \sec$.