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Q.
The distance between the poles of a horse shoe magnet is $0.1\, m$ and its pole strength is $0.01\, amp-m$. The induction of magnetic field at a point midway between the poles will be
Solution:
Net magnetic field at mid-point $P, B=B_{N}+B_{S}$
where $B_{N}=$ magnetic field due to $N$-pole
$B_{S}=$ Magnétic field due to $S$-pole
$B_{N}=B_{S}=\frac{\mu_{0}}{4 \pi} \frac{m}{r^{2}}$
$=10^{-7} \times \frac{0.01}{\left(\frac{0.1}{2}\right)^{2}}=4 \times 10^{-7} T$
$\therefore B_{\text {net }}=8 \times 10^{-7} T$
