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Q. The distance between the parallel lines $ y=x+a,\,\,y=x+b $ is

J & K CETJ & K CET 2008Straight Lines

Solution:

The distance between two parallel lines
$ =\frac{|{{c}_{1}}-{{c}_{2}}|}{\sqrt{{{a}^{2}}+{{b}^{2}}}} $
$ \therefore $ Distance $ =\frac{|b-a|}{\sqrt{{{1}^{2}}+{{1}^{2}}}} $ $ =\frac{|b-a|}{\sqrt{2}} $