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Q.
The distance between the lines $5x - 12y + 65 = 0$ and $10x - 24y - 39 = 0$ is
Straight Lines
Solution:
Given lines are $5x - 12y + 65 = 0$
and $10x- 24y-39 = 0$
$\Rightarrow 5x-12y-\frac{39}{2}=0$
Since, given lines are parallel.
$\therefore $ Distance between the lines
$=\frac{\left|-\frac{39}{2}-65\right|}{\sqrt{5^{2}+\left(-2\right)^{2}}}=\frac{\left|-\frac{169}{2}\right|}{\sqrt{25+144}}$
$=\frac{\frac{169}{2}}{13}=\frac{13}{2}$ units