Q. The distance between the centres of carbon and oxygen atoms in the carbon monoxide molecule is $ 1.130\,\mathring{A} $ . Locate the centre of mass of Ac molecule relative to the carbon atom:
KEAMKEAM 2006
Solution:
$ {{x}_{CM}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}}{{{m}_{1}}+{{m}_{2}}} $
$ \therefore $ $ {{x}_{CM}}=\frac{(12\times 0)+(16\times 1.13)}{12+16}=0.6457 \mathring{A} $
