1. Tardigrade
  2. Question
  3. Chemistry
  4. The dissociation constants for acetic acid and HCN at 25° C are 1.5 × 10-5 and 4.5 × 10-10 respectively. The equilibrium constant for the equilibrium CN -+ CH 3 COOH leftharpoons HCN + CH 3 COO - would be :

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Q. The dissociation constants for acetic acid and $HCN$ at $25^{\circ} C$ are $1.5 \times 10^{-5}$ and $4.5 \times 10^{-10}$ respectively. The equilibrium constant for the equilibrium
$CN ^{-}+ CH _{3} COOH \rightleftharpoons HCN + CH _{3} COO ^{-}$ would be :

AIPMTAIPMT 2009Equilibrium

Solution:

$CH _{3} COOH \Leftrightarrow CH _{3} COO ^{-}+ H ^{+} ; K _{a}=1.5 \times 10-5$
$H ^{+}+ CN ^{-} HCN ; \frac{1}{ K _{a}}=\frac{1}{4.5 \times 10^{-10}}$
$K _{ a }$ for $CN { }^{-}+ CH _{3} COOH \Leftrightarrow CH _{3} COO ^{-}+ HCN$ is
$\frac{1.5 \times 10^{-5}}{4.5 \times 10^{-10}}=\frac{1}{3} \times 10^{5}=3 \times 10^{4}$